{"componentChunkName":"component---src-templates-blog-post-js","path":"/algorithm/codility/lesson15/ 36-countTriangles/","result":{"data":{"site":{"siteMetadata":{"title":"Zayden","author":"[Your Name]","siteUrl":"https://gatsby-starter-bee.netlify.com","comment":{"disqusShortName":"","utterances":"JaeYeopHan/gatsby-starter-bee"},"sponsor":{"buyMeACoffeeId":"jbee"}}},"markdownRemark":{"id":"24a9219a-b93c-575b-bc84-950f413dfbc9","excerpt":"문제 설명 N개의 정수로 구성된 배열 A가 주어집니다. 삼중항(P, Q, R)은 변의 길이가 AP, AQ, AR인 삼각형을 만들 수 있다면 삼각형입니다. 즉, 삼중항(P, Q, R)은 0 ≤ P < Q < R < N이면 삼각형입니다: 예를 들어 다음과 같은 배열 A를 생각해 봅시다: 이 배열의 요소로 구성할 수 있는 삼각형 삼중항은 (0, 2, 4), (0, 2, 5), (0, 4, 5), (2, 4, 5) 등 네 가지가 있습니다. 함수를 작성합니다: 이 함수는 N개의 정수로 구성된 배열 A…","html":"<h2 id=\"문제-설명\" style=\"position:relative;\"><a href=\"#%EB%AC%B8%EC%A0%9C-%EC%84%A4%EB%AA%85\" aria-label=\"문제 설명 permalink\" class=\"anchor before\"><svg aria-hidden=\"true\" focusable=\"false\" height=\"16\" version=\"1.1\" viewBox=\"0 0 16 16\" width=\"16\"><path fill-rule=\"evenodd\" d=\"M4 9h1v1H4c-1.5 0-3-1.69-3-3.5S2.55 3 4 3h4c1.45 0 3 1.69 3 3.5 0 1.41-.91 2.72-2 3.25V8.59c.58-.45 1-1.27 1-2.09C10 5.22 8.98 4 8 4H4c-.98 0-2 1.22-2 2.5S3 9 4 9zm9-3h-1v1h1c1 0 2 1.22 2 2.5S13.98 12 13 12H9c-.98 0-2-1.22-2-2.5 0-.83.42-1.64 1-2.09V6.25c-1.09.53-2 1.84-2 3.25C6 11.31 7.55 13 9 13h4c1.45 0 3-1.69 3-3.5S14.5 6 13 6z\"></path></svg></a>문제 설명</h2>\n<p>N개의 정수로 구성된 배열 A가 주어집니다. 삼중항(P, Q, R)은 변의 길이가 A[P], A[Q], A[R]인 삼각형을 만들 수 있다면 삼각형입니다. 즉, 삼중항(P, Q, R)은 0 ≤ P &#x3C; Q &#x3C; R &#x3C; N이면 삼각형입니다:</p>\n<div class=\"gatsby-highlight\" data-language=\"text\"><pre class=\"language-text\"><code class=\"language-text\">A[P] + A[Q] > A[R],\na[q] + a[r] > a[p],\na[r] + a[p] > a[q].</code></pre></div>\n<p>예를 들어 다음과 같은 배열 A를 생각해 봅시다:</p>\n<div class=\"gatsby-highlight\" data-language=\"text\"><pre class=\"language-text\"><code class=\"language-text\">  a[0] = 10 a[1] = 2 a[2] = 5\n  a[3] = 1 a[4] = 8 a[5] = 12</code></pre></div>\n<p>이 배열의 요소로 구성할 수 있는 삼각형 삼중항은 (0, 2, 4), (0, 2, 5), (0, 4, 5), (2, 4, 5) 등 네 가지가 있습니다.</p>\n<p>함수를 작성합니다:</p>\n<div class=\"gatsby-highlight\" data-language=\"javascript\"><pre class=\"language-javascript\"><code class=\"language-javascript\"><span class=\"token keyword\">function</span> <span class=\"token function\">solution</span><span class=\"token punctuation\">(</span><span class=\"token parameter\"><span class=\"token constant\">A</span></span><span class=\"token punctuation\">)</span><span class=\"token punctuation\">;</span></code></pre></div>\n<p>이 함수는 N개의 정수로 구성된 배열 A가 주어지면 이 배열에 있는 삼각형 삼중 항의 개수를 반환합니다.</p>\n<p>예를 들어 배열 A가 주어지면</p>\n<div class=\"gatsby-highlight\" data-language=\"text\"><pre class=\"language-text\"><code class=\"language-text\">  a[0] = 10 a[1] = 2 a[2] = 5\n  a[3] = 1 a[4] = 8 a[5] = 12</code></pre></div>\n<p>이면 위에서 설명한 대로 함수는 4를 반환해야 합니다.</p>\n<p>다음 가정에 대한 효율적인 알고리즘을 작성합니다:</p>\n<ul>\n<li>N은 [0..1,000] 범위 내의 정수입니다;</li>\n<li>배열 A의 각 요소는 [1..1,000,000,000] 범위 내의 정수입니다.</li>\n</ul>\n<h2 id=\"문제-접근\" style=\"position:relative;\"><a href=\"#%EB%AC%B8%EC%A0%9C-%EC%A0%91%EA%B7%BC\" aria-label=\"문제 접근 permalink\" class=\"anchor before\"><svg aria-hidden=\"true\" focusable=\"false\" height=\"16\" version=\"1.1\" viewBox=\"0 0 16 16\" width=\"16\"><path fill-rule=\"evenodd\" d=\"M4 9h1v1H4c-1.5 0-3-1.69-3-3.5S2.55 3 4 3h4c1.45 0 3 1.69 3 3.5 0 1.41-.91 2.72-2 3.25V8.59c.58-.45 1-1.27 1-2.09C10 5.22 8.98 4 8 4H4c-.98 0-2 1.22-2 2.5S3 9 4 9zm9-3h-1v1h1c1 0 2 1.22 2 2.5S13.98 12 13 12H9c-.98 0-2-1.22-2-2.5 0-.83.42-1.64 1-2.09V6.25c-1.09.53-2 1.84-2 3.25C6 11.31 7.55 13 9 13h4c1.45 0 3-1.69 3-3.5S14.5 6 13 6z\"></path></svg></a>문제 접근</h2>\n<p><em>삼각형 조건을 배열 A를 오름 차순으로 정렬하면 하나의 조건만 고려하면된다.</em></p>\n<div class=\"gatsby-highlight\" data-language=\"javascript\"><pre class=\"language-javascript\"><code class=\"language-javascript\"><span class=\"token keyword\">function</span> <span class=\"token function\">solution</span><span class=\"token punctuation\">(</span><span class=\"token parameter\"><span class=\"token constant\">A</span></span><span class=\"token punctuation\">)</span> <span class=\"token punctuation\">{</span>\n    <span class=\"token keyword\">const</span> arr <span class=\"token operator\">=</span> <span class=\"token constant\">A</span><span class=\"token punctuation\">.</span><span class=\"token function\">slice</span><span class=\"token punctuation\">(</span><span class=\"token punctuation\">)</span><span class=\"token punctuation\">.</span><span class=\"token function\">sort</span><span class=\"token punctuation\">(</span><span class=\"token punctuation\">(</span><span class=\"token parameter\">a<span class=\"token punctuation\">,</span> b</span><span class=\"token punctuation\">)</span> <span class=\"token operator\">=></span> a <span class=\"token operator\">-</span> b<span class=\"token punctuation\">)</span><span class=\"token punctuation\">;</span>\n    <span class=\"token keyword\">let</span> result <span class=\"token operator\">=</span> <span class=\"token number\">0</span><span class=\"token punctuation\">;</span>\n\n    <span class=\"token keyword\">for</span> <span class=\"token punctuation\">(</span><span class=\"token keyword\">let</span> p <span class=\"token operator\">=</span> <span class=\"token number\">0</span><span class=\"token punctuation\">;</span> p <span class=\"token operator\">&lt;</span> arr<span class=\"token punctuation\">.</span>length <span class=\"token operator\">-</span> <span class=\"token number\">2</span><span class=\"token punctuation\">;</span> p<span class=\"token operator\">++</span><span class=\"token punctuation\">)</span> <span class=\"token punctuation\">{</span>\n        <span class=\"token keyword\">let</span> r <span class=\"token operator\">=</span> p <span class=\"token operator\">+</span> <span class=\"token number\">2</span><span class=\"token punctuation\">;</span>\n\n        <span class=\"token keyword\">for</span> <span class=\"token punctuation\">(</span><span class=\"token keyword\">let</span> q <span class=\"token operator\">=</span> p <span class=\"token operator\">+</span> <span class=\"token number\">1</span><span class=\"token punctuation\">;</span> q <span class=\"token operator\">&lt;</span> arr<span class=\"token punctuation\">.</span>length <span class=\"token operator\">-</span> <span class=\"token number\">1</span><span class=\"token punctuation\">;</span> q<span class=\"token operator\">++</span><span class=\"token punctuation\">)</span> <span class=\"token punctuation\">{</span>\n            <span class=\"token keyword\">while</span><span class=\"token punctuation\">(</span>arr<span class=\"token punctuation\">[</span>p<span class=\"token punctuation\">]</span> <span class=\"token operator\">+</span> arr<span class=\"token punctuation\">[</span>q<span class=\"token punctuation\">]</span> <span class=\"token operator\">></span> arr<span class=\"token punctuation\">[</span>r<span class=\"token punctuation\">]</span><span class=\"token punctuation\">)</span> <span class=\"token punctuation\">{</span>\n                r<span class=\"token operator\">++</span><span class=\"token punctuation\">;</span>\n            <span class=\"token punctuation\">}</span>\n\n            result <span class=\"token operator\">+=</span> r <span class=\"token operator\">-</span> q <span class=\"token operator\">-</span> <span class=\"token number\">1</span><span class=\"token punctuation\">;</span>\n        <span class=\"token punctuation\">}</span>\n    <span class=\"token punctuation\">}</span>\n\n    <span class=\"token keyword\">return</span> result<span class=\"token punctuation\">;</span>\n<span class=\"token punctuation\">}</span></code></pre></div>","frontmatter":{"title":"Codility Lesson 15 - CountTriangles","date":"July 18, 2023"}}},"pageContext":{"slug":"/algorithm/codility/lesson15/ 36-countTriangles/","previous":{"fields":{"slug":"/algorithm/codility/lesson15/ 35-countDistinctSlices/"},"frontmatter":{"title":"Codility Lesson 15 - CountDistinctSlices"}},"next":{"fields":{"slug":"/algorithm/codility/lesson15/ 37-minAbsSumOfTwo/"},"frontmatter":{"title":"Codility Lesson 15 - MinAbsSumOfTwo"}}}}}